18x^2=-48x+32

Solution for 18x^2=-48x+32 equation:

18x^2=-48x+32

We move all terms to the left:

18x^2-(-48x+32)=0

We get rid of parentheses

18x^2+48x-32=0

a = 18; b = 48; c = -32;
Δ = b2-4ac
Δ = 482-4·18·(-32)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48\sqrt{2}}{2*18}=\frac{-48-48\sqrt{2}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48\sqrt{2}}{2*18}=\frac{-48+48\sqrt{2}}{36}
$